11
Tensors as multilinear forms\\
Handout ``Methoden der Theoretischen Physik-\"Ubungen''
Tensors as multilinear forms
Handout ``Methoden der Theoretischen Physik-Übungen''
Karl Svozil
Abstract
Tensors are defined as multilinear forms on vector spaces
1 Notation
Consider the vector space \Bbb RD of dimension D,
a basis
\mathfrak B={e1,e2,¼,eD} consisting of
D basis vectors ei,
and n arbitrary vectors
x1,x2,¼,xn Î \Bbb RD
with vector components
Xi1,Xi2,¼,Xin Î \Bbb R.
Tensor fields define tensors in every point of \Bbb RD separately.
In general, with respect to a particular basis, the components of a tensor field
depend on the coordinates.
We adopt Einstein's summation convention to sum over equal indices
(one pair with a superscript and a subscript).
Sometimes, sums are written out explicitly.
In what follows, the notations
`` x·y'',
`` (x,y)'' and
`` áx | yñ'' will be used synonymously for the
scalar product.
Note, however, that the notation `` x·y''
may be a little bit misleading; e.g. in the case of the ``pseudo-Euclidean'' metric
diag(+,+,+,¼,+,-).
For a more systematic treatment, see for instance Klingbeil
[1]
and Dirschmid
[2].
.
2 Multilinear form
A multilinear form
is a map satisfying
|
a( x1,x2,¼, A x1i+ B x2i,¼,xn) |
|
|
| |
|
| (2) |
|
for every one of its (multi-)arguments.
3 Covariant tensors
A tensor of rank n
is a multilinear form
|
a( x1,x2,¼,xn) = |
D å
i1=1
|
|
D å
i2=1
|
¼ |
D å
in=1
|
Xii1 Xi22¼Xinna( ei1,ei2,¼,ein). |
| (4) |
The
|
Ai1i2¼in=a( ei1,ei2,¼,ein) |
| (5) |
are the
components of the tensor a with respect to the basis
\mathfrak B.
3.0.1 Question: how many components are there?
Answer: Dn.
3.0.2 Question: proof that tensors are multilinear forms.
Answer:
by insertion.
|
|
|
|
a( x1,x2,¼, Ax1j+Bxj2,¼,xn) |
| |
|
|
|
D å
i1=1
|
|
D å
i2=1
|
¼ |
D å
in=1
|
Xii1Xi22¼[A(X1)ijj+B(X2)ijj]¼Xinna( ei1,ei2,¼,eij,¼,ein) |
| |
|
|
A |
D å
i1=1
|
|
D å
i2=1
|
¼ |
D å
in=1
|
Xii1Xi22¼(X1)ijj¼Xinna( ei1,ei2,¼,eij,¼,ein) |
| |
|
|
+B |
D å
i1=1
|
|
D å
i2=1
|
¼ |
D å
in=1
|
Xii1Xi22¼(X2)ijj¼Xinna( ei1,ei2,¼,eij,¼,ein) |
| |
|
| A a( x1,x2,¼, x1j,¼,xn)+B a( x1,x2,¼, xj2,¼,xn) |
|
|
3.1 Basis transformations
Let
\mathfrak B
and
\mathfrak B¢
be two arbitrary bases of
\Bbb RD.
Then ervery vector e¢i of
\mathfrak B¢
can be represented as linear combination of basis vectors from
\mathfrak B:
|
e¢i= |
D å
j=1
|
aij ej, i=1,¼, D . |
| (6) |
(Formally, we may treat e¢i and ei
as scalar variables e¢i and ej, respectively; such that
aij = [(¶ e¢i)/(¶ ej)].)
Consider an arbitrary vector x Î \Bbb RD
with components Xi with respect to the basis
\mathfrak B
and X¢i with respect to the basis
\mathfrak B¢:
|
x = |
D å
i=1
|
Xi ei = |
D å
i=1
|
X¢i e¢i. |
| (7) |
Insertion into (6) yields
|
x = |
D å
i=1
|
Xi ei = |
D å
i=1
|
X¢i e¢i = |
D å
i=1
|
X¢i |
D å
j=1
|
aij ej = |
D å
i=1
|
|
é ë
|
D å
j=1
|
aijX¢i |
ù û
|
ej. |
| (8) |
A comparison of coefficient yields the transformation laws of vector components
The matrix a={aij} is called the transformation matrix.
In terms of the coordinates Xj, it can be expressed as
A similar argument using
|
ei= |
D å
j=1
|
a¢ij e¢j, i=1,¼, D |
| (11) |
yields the inverse transformation laws
(Again, formally, we may treat e¢i and ei
as scalar variables e¢i and ej, respectively; such that
a¢ij = [(¶ei)/(¶ e¢j)].)
Thereby,
|
ei= |
D å
j=1
|
a¢ij e¢j = |
D å
j=1
|
a¢ij |
D å
k=1
|
ajk ek = |
D å
j=1
|
|
D å
k=1
|
[a¢ij ajk] ek, |
| (13) |
which, due to the linear independence of the basis vectors ei od \mathfrak B,
is only satisfied if
|
a¢ij ajk = dik or a¢a=\Bbb I. |
| (14) |
That is, a¢ is the inverse matrix of a.
In terms of the coordinates Xj, it can be expressed as
3.2 Transformation of Tensor components
Because of multilinearity (!) and by insertion into
(6),
|
|
|
|
a( e¢j1,e¢j2,¼,e¢jn) = a |
æ è
|
D å
i1=1
|
aj1i1 ei1, |
D å
i2=1
|
aj2i2 ei2,¼, |
D å
in=1
|
ajnin ein |
ö ø
|
|
| |
|
| = |
D å
i1=1
|
|
D å
i2=1
|
¼ |
D å
in=1
|
aj1i1aj2i2¼ajnin a( ei1,ei2,¼,ein) |
| (16) |
|
or
|
A¢j1j2¼jn = |
D å
i1=1
|
|
D å
i2=1
|
¼ |
D å
in=1
|
aj1i1aj2i2¼ajnin Ai1 i2¼in. |
| (17) |
4 Contravariant tensors
4.1 Definition of contravariant basis
Consider again a covariant basis
\mathfrak B={e1,e2,¼,eD} consisting of
D basis vectors ei.
We shall define now a contravariant basis
\mathfrak B*={e1,e2,¼,eD} consisting of
D basis vectors ei
by the requirement that the scalar product obeys
|
dij = ei·ej º (ei,ej) º áei | ejñ = |
ì ï í
ï î
|
|
. |
| (18) |
To distinguish elements of the two bases, the covariant vectors are denoted by subscripts,
whereas the contravariant vectors are denoted by superscripts.
The last term ei·ej º (ei,ej) º áei | ejñ
recalls different notations of the scalar product.
The entire tensor formalism developed so far can be applied to define contravariant tensors
as multinear forms
by
|
b( x1,x2,¼,xn) = |
D å
i1=1
|
|
D å
i2=1
|
¼ |
D å
in=1
|
Xi11 Xi22¼Xinnb( ei1,ei2,¼,ein). |
| (20) |
The
|
Bi1i2¼in=b( ei1,ei2,¼,ein) |
| (21) |
are the
components of the contravariant tensor b with respect to the basis
\mathfrak B*.
4.2 Connection between the transformation of covariant and contravariant entities
Because of linearity, we can make the Ansatz
where {bij}=b is
the transformation matrix associated with the contravariant basis.
How is b related to a,
the transformation matrix associated with the covariant basis?
By exploiting (18) one can find the connection between
the transformation of covariant and contravariant basis elements and thus
tensor components.
|
dij = e¢i·e¢j=(aikek)·(bljel)=aikblj ek·el=aikblj dkl = aikbkj, |
| (23) |
and
The entire argument concerning transformations of covariant tensors and components
can be carried through to the contravariant case.
Hence, the contravariant components transform as
|
|
|
|
b( e¢j1,e¢j2,¼,e¢jn) = b |
æ è
|
D å
i1=1
|
a¢j1i1 ei1, |
D å
i2=1
|
a¢j2i2 ei2,¼, |
D å
in=1
|
a¢jnin ein |
ö ø
|
|
| |
|
| = |
D å
i1=1
|
|
D å
i2=1
|
¼ |
D å
in=1
|
a¢j1i1a¢j2i2¼a¢jnin b( ei1,ei2,¼,ein) |
| (25) |
|
or
|
B¢j1j2¼jn = |
D å
i1=1
|
|
D å
i2=1
|
¼ |
D å
in=1
|
a¢j1i1a¢j2i2¼a¢jnin Bi1 i2¼in. |
| (26) |
5 Orthonormal bases
For orthonormal bases,
and thus the two bases are identical
and formally any distinction between covariant and contravariant vectors becomes
irrelevant. Conceptually, such a distinction persists, though.
6 Invariant tensors and physical motivation
7 Metric tensor
Metric tensors are defined in metric vector spaces.
A metric vector space (sometimes also refered to
as ``vector space with metric'' or ``geometry'')
is a vector space with inner or scalar product.
This includes (pseudo-) Euclidean spaces with indefinite metric.
(I.e., the distance needs not be positive or zero.)
7.1 Definition inner or scalar product
The scalar or inner product,
is a symmetric bilinear functional
\Bbb RD×\Bbb RD® \Bbb R
such that
- (x+y,z)=(x,z)+(y,z) for all x,y,z Î \Bbb RD;
-
(x,y+z)=(x,y)+(x,z) for all x,y,z Î \Bbb RD;
-
(ax,y)=a(x,y) for all x,y Î \Bbb RD, a Î \Bbb R;
-
(x,ay)=a(x,y) for all x,y Î \Bbb RD, a Î \Bbb R;
-
(x,y)=(y,x) for all x,y Î \Bbb RD
Axioms 1 and 3 assert that the scalar product is linear in the first variable.
Axioms 2 and 4 assert that the scalar product is linear in the second variable.
Axiom 5 asserts the bilinear function is symmetric.
7.2 Definition metric
A metric is a functional \Bbb RD® \Bbb R
with the following properties
- ||x -y || = 0 Û x = y,
-
||x- y|| = ||x- y|| (symmetry),
-
||x-z|| £ ||x- y||+ ||y- z|| (triangle
inequality).
7.3 Construction of a metric from a scalar product by metric tensor
The metric tensor is defined by the scalar product
|
gij=ei·ej º (ei, ej) º áei, ejñ. |
| (29) |
and
|
gij=ei·ej º (ei, ej) º áei, ejñ. |
| (30) |
Likewise,
|
gij=ei·ej º (ei, ej) º áei, ejñ = dij . |
| (31) |
Note that it easy to change a covarant tensor into a contravariant and vice versa
by the application of a metric tensor.
This can be seen as follows.
Because of linearity, any contravariant basis vector ei
can be written as a linear sum of covariant basis vectors:
Then,
|
gik = ei·ek = (Aijej)·ek=Aij(ej·ek)=Aijdjk=Aik |
| (33) |
and thus
and
Question: Show that, for orthonormal basis, the metric tensor can be
represented as a Kronecker delta function in all basis (form invariant);
i.e.,
dij,dij,dij,dij.
Question: Why is g a tensor? Show its multilinearity.
7.4 What can the metric tensor do for us?
Most often it is used to raise/lower the indices; i.e.,
to change from contravariant to covariant and conversely from covariant
to contravariant.
In the previous section, the metric tensor has been derived from the scalar product.
The converse is true as well.
The metric tensor represents the scalar product between vectors: let
x=Xiei Î \Bbb RD and y=Yjej Î \Bbb RD be two vectors.
Then ("T" stands for the transpose),
|
x·y º (x,y) º áx | yñ = Xi ei·Yj ej = XiYj ei·ej = XiYj gij = XT g Y. |
| (36) |
It also characterizes the length of a vector: in the above
equation, set y=x. Then,
|
x·x º (x,x) º áx | xñ = XiXj gij º XT g X, |
| (37) |
and thus
|
||x|| = | Ö
|
XiXj gij
|
= | Ö
|
XT g X
|
. |
| (38) |
The square of an infinitesimal vector ds = {dxi} is
|
(d s)2 = gijdxidxj = dxT g dx. |
| (39) |
Question: Prove that ||x|| mediated by g is
indeed a metric.
7.5 Transformation of the metric tensor
Insertion into the definitions and coordinate transformations
(10)
and
(15)
yields
|
gij=ei·ej = a¢lie¢l·a¢mje¢m = a¢li a¢mj e¢l·e¢m = a¢li a¢mj g¢lm = |
¶X¢l
¶Xi
|
|
¶X¢m
¶Xj
|
g¢lm. |
| (40) |
Conversely,
|
g¢ij=e¢i·e¢j = aliel·amjem = ali amj el·em = ali amj glm = |
¶Xl
¶X¢i
|
|
¶Xm
¶X¢j
|
glm. |
| (41) |
If the geometry (i.e., the basis) is locally orthonormal, glm=dlm,
then
g¢ij=[(¶Xl)/(¶X¢i)][(¶Xl)/(¶X¢j)].
7.6 Examples
For a more systematic treatment, see for instance Snapper&Troyer [3].
7.6.1 D-dimensional Euclidean space
|
g º {gij}=diag ( |
1,1,¼,1 D times
|
) |
| (42) |
One application in physics is quantum mechanics,
where D stands for the dimension of a complex Hilbert space.
All definitions can be easily adopted to accommodate the complex numbers.
E.g., axiom 5 of the scalar product becomes
(x,y)=(x,y)*, where `` * '' stands for complex conjugation.
Axiom 4 of the scalar product becomes
(x,ay)=a* (x,y).
7.6.2 Lorentz plane
7.6.3 Minkowski space of dimension D
In this case the metric tensor is called the Minkowski metric and is often denoted by ``h'':
|
h º {hij}=diag ( |
1,1,¼,1 D-1 times
|
,-1) |
| (44) |
One application in physics is the theory of special relativity,
where D=4.
Alexandrov's theorem states that the mere requirement of the preservation of
zero distance (i.e., lightcones), combined with bijectivity of the transformation law
yields the Lorentz transformations
([4,5,6,7,8]
are original articles reviewed in [9,10];
see also
[11] for an elementary proof).
7.6.4 Negative Euclidean space of dimension D
|
g º {gij}=diag ( |
-1,-1,¼,-1 D times
|
) |
| (45) |
7.6.5 Artinian four-space
|
g º {gij}=diag (+1,+1,-1 ,-1) |
| (46) |
7.6.6 General relativity
In general relativity, the metric tensor g is linked to the energy-mass distribution.
There, it appears as the primary concept when compared to the scalar product.
In the case of zero gravity, g is just the Minkowski metric (often denoted by ``h'')
diag (1,1,1,-1) corresponding to ``flat'' space-time.
The best known non-flat metric is the Schwarzschild metric
|
g º |
æ ç ç ç ç
ç ç ç è
|
| |
ö ÷ ÷ ÷ ÷
÷ ÷ ÷ ø
|
|
| (47) |
with respect to the spherical space-time coordinates r,q,f,t.
7.6.7 Computation of the metric tensor of the ball
Consider the transformation from the standard orthonormal
three-dimensional ``cartesian'' coordinates
X1=x,
X2=y,
X3=z,
into spherical coordinates
X1¢=r,
X2¢=q,
X3¢=j.
In terms of r,q, j, the cartesian coordinates can be written as
X1=r sinqcosj º X1¢sinX2¢cosX3¢,
X2=r sinqsinj º X1¢sinX2¢sinX3¢,
X3=r cosq º X1¢cosX2¢.
Furthermore, since we are dealing with the cartesian orthonormal basis,
gij=dij; hence finally
|
g¢ij = |
¶Xl
¶X¢i
|
|
¶Xl
¶X¢j
|
º diag(1,r2,r2sin2 q), |
| (48) |
and
|
(ds)2 = (dr)2+r2(dq)2+r2sin2 q(dj)2. |
| (49) |
The expression (ds)2 = (dr)2+r2(dj)2
for polar coordinates (D=2) is obtained by setting q = p/4 and dq = 0.
7.6.8 Computation of the metric tensor of the Moebius strip
Parameter representation of the Moebius strip:
|
F(u,v) = |
æ ç ç ç ç ç
ç ç ç ç è
|
|
ö ÷ ÷ ÷ ÷ ÷
÷ ÷ ÷ ÷ ø
|
|
| (50) |
with
u Î [0,2p] represents the position of the point on the circle,
and v Î [-a,a] a > 0, where 2a is the ``width'' of the Moebius strip.
|
|
|
|
|
¶F
¶v
|
=\allowbreak |
æ ç ç ç ç ç
ç ç ç ç è
|
|
ö ÷ ÷ ÷ ÷ ÷
÷ ÷ ÷ ÷ ø
|
|
| (51) | |
|
|
¶F
¶u
|
=\allowbreak |
æ ç ç ç ç ç
ç ç ç ç è
|
|
- |
1
2
|
vsin |
1
2
|
usinu+ |
æ è
|
1+vcos |
1
2
|
u |
ö ø
|
cosu |
|
|
- |
1
2
|
vsin |
1
2
|
ucosu- |
æ è
|
1+vcos |
1
2
|
u |
ö ø
|
sinu |
|
|
|
ö ÷ ÷ ÷ ÷ ÷
÷ ÷ ÷ ÷ ø
|
|
| (52) |
|
|
|
|
|
\allowbreak |
æ ç ç ç ç ç
ç ç ç ç è
|
|
ö ÷ ÷ ÷ ÷ ÷
÷ ÷ ÷ ÷ ø
|
T
|
|
æ ç ç ç ç ç
ç ç ç ç è
|
|
- |
1
2
|
vsin |
1
2
|
usinu+ |
æ è
|
1+vcos |
1
2
|
u |
ö ø
|
cosu |
|
|
- |
1
2
|
vsin |
1
2
|
ucosu- |
æ è
|
1+vcos |
1
2
|
u |
ö ø
|
sinu |
|
|
|
ö ÷ ÷ ÷ ÷ ÷
÷ ÷ ÷ ÷ ø
|
|
| |
|
|
- |
1
2
|
|
æ è
|
cos |
1
2
|
usin2u |
ö ø
|
vsin |
1
2
|
u- |
1
2
|
|
æ è
|
cos |
1
2
|
ucos2u |
ö ø
|
vsin |
1
2
|
u |
| |
|
| + |
1
2
|
|
æ è
|
sin |
1
2
|
u |
ö ø
|
vcos |
1
2
|
u=\allowbreak 0 |
| (53) |
|
|
|
|
|
\allowbreak |
æ ç ç ç ç ç
ç ç ç ç è
|
|
ö ÷ ÷ ÷ ÷ ÷
÷ ÷ ÷ ÷ ø
|
T
|
|
æ ç ç ç ç ç
ç ç ç ç è
|
|
ö ÷ ÷ ÷ ÷ ÷
÷ ÷ ÷ ÷ ø
|
|
| |
|
| cos2 |
1
2
|
usin2u+cos2 |
1
2
|
ucos2u+sin2 |
1
2
|
u=\allowbreak 1 |
| (54) |
|
|
|
|
|
\allowbreak |
æ ç ç ç ç ç
ç ç ç ç è
|
|
- |
1
2
|
vsin |
1
2
|
usinu+ |
æ è
|
1+vcos |
1
2
|
u |
ö ø
|
cosu |
|
|
- |
1
2
|
vsin |
1
2
|
ucosu- |
æ è
|
1+vcos |
1
2
|
u |
ö ø
|
sinu |
|
|
|
ö ÷ ÷ ÷ ÷ ÷
÷ ÷ ÷ ÷ ø
|
T
|
|
æ ç ç ç ç ç
ç ç ç ç è
|
|
- |
1
2
|
vsin |
1
2
|
usinu+ |
æ è
|
1+vcos |
1
2
|
u |
ö ø
|
cosu |
|
|
- |
1
2
|
vsin |
1
2
|
ucosu- |
æ è
|
1+vcos |
1
2
|
u |
ö ø
|
sinu |
|
|
|
ö ÷ ÷ ÷ ÷ ÷
÷ ÷ ÷ ÷ ø
|
|
| |
|
|
|
1
4
|
v2sin2 |
1
2
|
usin2u+cos2u+2( cos2u) vcos |
1
2
|
u+( cos2u)v2cos2 |
1
2
|
u |
| |
|
|
+ |
1
4
|
v2sin2 |
1
2
|
ucos2u+sin2u+2( sin2u) vcos |
1
2
|
u+( sin2u) v2cos2 |
1
2
|
u |
| |
|
|
+ |
1
4
|
v2cos2 |
1
2
|
u = \allowbreak |
1
4
|
v2+v2cos2 |
1
2
|
u+1+2vcos |
1
2
|
u |
| |
|
| (55) |
|
Thus the metric tensor is given by
|
g¢ij = |
¶Xs
¶X¢i
|
|
¶Xt
¶X¢j
|
gst = = |
¶Xs
¶X¢i
|
|
¶Xt
¶X¢j
|
dst º |
æ ç
è
|
|
ö ÷
ø
|
=diag |
æ è
|
(1+vcos( |
u
2
|
))2+ |
1
4
|
v2 , 1 |
ö ø
|
. |
| (56) |
8 Invariant tensors and physical motivation
What makes some touples (or matrix, or tensor components in general) of
numbers or scalar functions a tensor? It is the
interpretation of the scalars as tensor components with respect to
a particular basis. In another basis, if we were talking about the same
tensor, the tensor components; i.e., the numbers or scalar functions
would be different.
The tensor components are scalars and can thus be treated as scalars.
For instance, due to commutativity and associativity, one can exchange
their order. (Notice, though, that this is generally not the case for
differential operators such as ¶i=¶/ ¶xi.)
A form invariant tensor with respect to certain transformations
is a tensor which retains
the same functional form if the transformations are performes; i.e.,
if the basis changes accordingly.
That is, numbers are mapped into the same numbers (not just any
numbers).
Functions remain the same but with the new parameter components as
arguement. For instance; 4® 4 and f(X1,X2,X3)®f(X¢1,X¢2,X¢3).
If a tensor is invariant with respect to one transformation, it need not
be invariant with respect to another transformation, or with respect to
changes of the scalar product; i.e., the metric.
Nevertheless, totally symmetric (antisymmetric) tensors remain totally
symmetric (antisymmetric) in all cases:
|
Ai1i2 ¼isit¼in = Ai1i2 ¼itis¼in |
|
|
|
A¢j1i2 ¼js jt¼jn = aj1i1aj2i2¼ajsisajtit¼ajnin Ai1 i2¼is it¼in |
| |
|
|
= aj1i1aj2i2¼ajsisajtit¼ajnin Ai1 i2¼it is¼in |
| |
|
|
= aj1i1aj2i2¼ajtitajsis¼ajnin Ai1 i2¼it is¼in |
| |
|
| (57) | |
Ai1i2 ¼isit¼in = -Ai1i2 ¼itis¼in = |
|
|
|
A¢j1i2 ¼js jt¼jn = aj1i1aj2i2¼ajsisajtit¼ajnin Ai1 i2¼is it¼in |
| |
|
|
= -aj1i1aj2i2¼ajsisajtit¼ajnin Ai1 i2¼it is¼in |
| |
|
|
= -aj1i1aj2i2¼ajtitajsis¼ajnin Ai1 i2¼it is¼in. |
| |
|
| (58) |
|
In physics, it would be nice if the natural laws could be written into a
form which does not depend on the particular reference frame or basis
used.
Form invariance thus is a gratifying physical feature, reflecting the
symmetry against changes of coordinated and bases.
Therefore, physicists tend to be crazy to write down everything in a
form invariant manner.
One strategy to accomplishe this to start out with form invariant
tensors and compose everything from them. This method guarantees form
invarince (at least in the 0'th order).
9 Some tricks
There are some tricks which are commonly used.
Here, some of them are enumerated:
- Indices which appear as internal sums can be renamed arbitrarily
(provided their name is not already taken by some other index).
-
With the euclidean metric, dii=D.
-
¶Xi /¶Xj=dij.
-
With the euclidean metric, ¶Xi /¶Xi=D.
-
For D=3 and the euclidean metric,
the Grassmann identity holds:
eijkeklm = dildjm-dimldjl.
-
For D=3 and the euclidean metric,
|a×b | = Ö{eijkeistajasbkbt} = Ö{|a|2|b|2-(a·b)2}=Ö{det(
)} = |a||b|sinqab.
-
Let u,v º X1¢,X2¢ be two parameters associated with an
orthonormal cartesian basis {(0,1),(1,0)} and let
F:(u,v)® \Bbb R3
be a mapping from some area of \Bbb R2 into a twodimensional
surface of \Bbb R3. Then the metric tensor is given by
gij = [(¶Fk)/(¶X¢i)][(¶Fm)/(¶X¢j)] dkm.
10 Some common misconceptions
10.1 Confusion between component representation and ``the real thing''
Given a particular basis, a tensor is uniquely characterized by its components.
However, without reference to a particular basis, any components are just blurbs.
Example (wrong!): a rank-1 tensor (i.e., a vector) is given by
(1,2).
Correct: with respect to the basis {(0,1),(1,0)}, a rank-1 tensor (i.e., a vector) is given by
(1,2).
10.2 A matrix is a tensor
See the above section.
Example (wrong!): A matrix is a tensor of rank 2.
Correct: with respect to the basis {(0,1),(1,0)}, a matrix represents a rank-2 tensor.
The matrix components are the tensor components.
10.3 Decomposition of tensors
Although a tensor of rank n transforms like the tensor product of n tensors of rank 1,
not all rank-n tensors can be decomposed into a single
tensor product of n tensors of rank 1.
Nevertheless, any rank-n tensor can be decomposed into
the sum of Dn
tensor products of n tensors of rank 1.
10.4 Form invariance of tensors
Although form invariance is a gratifying feature,
a tensor (field) needs not be form invariant.
Indeed,
while
is a form invariant tensor field with respect to the basis {(0,1),(1,0)}
and orthogonal transformations (rotations around the origin)
is not (please verify).
This, however, does not mean that
T is not a respectable tensor field; its just not form invariant under rotations.
Note that the tensor product of form invariant tensors is again a form invariant tensor.
References
- [1]
-
Ebergard Klingbeil.
Tensorrechnung für Ingenieure.
Bibliographisches Institut, Mannheim, 1966.
- [2]
-
Hans Jörg Dirschmid.
Tensoren und Felder.
Springer, Vienna, 1996.
- [3]
-
Ernst Snapper and Robert J. Troyer.
Metric Affine Geometry.
Academic Press, New York, 1971.
- [4]
-
A. D. Alexandrov.
On Lorentz transformations.
Uspehi Mat. Nauk., 5(3):187, 1950.
- [5]
-
A. D. Alexandrov.
A contribution to chronogeometry.
Canadian Journal of Math., 19:1119-1128, 1967.
- [6]
-
A. D. Alexandrov.
Mappings of spaces with families of cones and space-time
transformations.
Annali die Matematica Pura ed Applicata, 103:229-257, 1967.
- [7]
-
A. D. Alexandrov.
On the principles of relativity theory.
In Classics of Soviet Mathematics. Volume 4. A. D. Alexandrov.
Selected Works, pages 289-318. 1996.
- [8]
-
H. J. Borchers and G. C. Hegerfeldt.
The structure of space-time transformations.
Communications in Mathematical Physics, 28:259-266, 1972.
- [9]
-
Walter Benz.
Geometrische Transformationen.
BI Wissenschaftsverlag, Mannheim, 1992.
- [10]
-
June A. Lester.
Distance preserving transformations.
In Francis Buekenhout, editor, Handbook of Incidence Geometry.
Elsevier, Amsterdam, 1995.
- [11]
-
Karl Svozil.
Conventions in relativity theory and quantum mechanics.
Foundations of Physics, 32:479-502, 2002.
e-print arXiv:quant-ph/0110054.
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